Given the system of equations:
\[ \begin{array}{l} 4x + 3y = -4 \\ y = 3x - 10 \end{array} \]
We substitute the expression for \( y \) from the second equation into the first equation:
\[ 4x + 3(3x - 10) = -4 \]
Distribute the 3 in the equation:
\[ 4x + 9x - 30 = -4 \]
Combine like terms:
\[ 13x - 30 = -4 \]
Add 30 to both sides of the equation:
\[ 13x = 26 \]
Divide both sides by 13:
\[ x = 2 \]
Substitute \( x = 2 \) back into the equation for \( y \):
\[ y = 3(2) - 10 \]
Simplify:
\[ y = 6 - 10 = -4 \]
The solution to the system of equations is:
\[ \boxed{x = 2} \]
\[ \boxed{y = -4} \]
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