Questions: What is the molarity of a 0.30 L solution with 43 g H2SO4? Select the correct answer below: 0.8 M 1.1 M 1.5 M 1.7 M

Transcript text: What is the molarity of a 0.30 L solution with $43 \mathrm{~g} \mathrm{H}_{2} \mathrm{SO}_{4}$ ? Select the correct answer below: 0.8 M 1.1 M 1.5 M 1.7 M

Solution

Solution Steps

Step 1: Calculate the Molar Mass of $ \mathrm{H}_2\mathrm{SO}_4 $

The molar mass of $ \mathrm{H}_2\mathrm{SO}_4 $ is calculated by summing the atomic masses of its constituent atoms:

Hydrogen (H): $ 2 \times 1.008 \, \text{g/mol} = 2.016 \, \text{g/mol} $
Sulfur (S): $ 1 \times 32.06 \, \text{g/mol} = 32.06 \, \text{g/mol} $
Oxygen (O): $ 4 \times 16.00 \, \text{g/mol} = 64.00 \, \text{g/mol} $

Adding these together gives the molar mass of $ \mathrm{H}_2\mathrm{SO}_4 $: \[ 2.016 + 32.06 + 64.00 = 98.076 \, \text{g/mol} \]

Step 2: Calculate the Number of Moles of $ \mathrm{H}_2\mathrm{SO}_4 $

To find the number of moles, use the formula: \[ \text{moles} = \frac{\text{mass}}{\text{molar mass}} \] Substituting the given values: \[ \text{moles} = \frac{43 \, \text{g}}{98.076 \, \text{g/mol}} \approx 0.4383 \, \text{mol} \]

Step 3: Calculate the Molarity of the Solution

Molarity (M) is defined as the number of moles of solute per liter of solution: \[ \text{Molarity} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \] Given that the volume of the solution is 0.30 L: \[ \text{Molarity} = \frac{0.4383 \, \text{mol}}{0.30 \, \text{L}} \approx 1.461 \, \text{M} \]