Questions: At 70 degrees C, the compound is in the gas phase, and at 20 degrees C the compound is in the solid phase. At 6 minutes, the compound is undergoing the phase change called From 13 minutes to 16 minutes, the compound is in the liquid phase.

At 70 degrees C, the compound is in the gas phase, and at 20 degrees C the compound is in the solid phase.

At 6 minutes, the compound is undergoing the phase change called

From 13 minutes to 16 minutes, the compound is in the liquid phase.

Transcript text: At 70 degrees $C$, the compound is in the gas phase, and at 20 degrees $C$ the compound is in the $\square$ solid phase. At 6 minutes, the compound is undergoing the phase change called $\square$ From 13 minutes to 16 minutes, the compound is in the $\square$ liquid phase.

Solution

Solution Steps

Step 1: Analyze the graph

The graph shows the temperature of a compound over time. We can determine the phase of the compound at different temperatures and times.

Step 2: Determine the phase at 70°C

At 70°C, the compound is in its liquid phase. This is because the temperature is high and the compound is cooling down.

Step 3: Determine the phase at 20°C

At 20°C, the compound is in its solid phase. This is because the temperature is low and the compound continues to cool down, reaching 0°C.

Step 4: Determine the phase change at 6 minutes

At 6 minutes, the temperature is constant at 60°C. This indicates that the compound is undergoing a phase change. Since the compound is cooling, it is transitioning from liquid to solid. This phase change is called freezing or solidification.

Step 5: Determine the phase from 13 minutes to 16 minutes

From 13 minutes to 16 minutes, the temperature of the compound is decreasing from 60°C to 35°C. Since the freezing point is 60°C, the compound is in the liquid phase until it reaches 60°C. Thus, from 13 minutes to 14 minutes (approximately), the compound is still in the liquid phase while from 14 to 16 it is in the solid phase.