Calculate the indefinite integral: $\int(x+3) dx$
Identify the terms in the integrand
The integrand is $(x+3)$, which can be separated into two terms: $x$ and $3$.
Apply the linearity property of integration
Using the property that $\int(f(x) + g(x))dx = \int f(x)dx + \int g(x)dx$, we can write:
$\int(x+3)dx = \int x dx + \int 3 dx$
Evaluate each integral separately
For $\int x dx$, we use the power rule: $\int x^n dx = \frac{x^{n+1}}{n+1} + C$ for $n \neq -1$
$\int x dx = \int x^1 dx = \frac{x^2}{2} + C_1$
For $\int 3 dx$, we integrate the constant:
$\int 3 dx = 3x + C_2$
Combine the results
$\int(x+3)dx = \frac{x^2}{2} + 3x + C$
Where $C = C_1 + C_2$ is the arbitrary constant of integration.
$\boxed{\int(x+3)dx = \frac{x^2}{2} + 3x + C}$
$\boxed{\int(x+3)dx = \frac{x^2}{2} + 3x + C}$