Questions: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 3.6 years, and standard deviation of 1.2 years.
If you randomly purchase one item, what is the probability it will last longer than 3 years?
Round answer to three decimal places.
Transcript text: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 3.6 years, and standard deviation of 1.2 years.
If you randomly purchase one item, what is the probability it will last longer than 3 years?
Round answer to three decimal places $\square$
Solution
Solution Steps
Step 1: Calculate the Z-score for the individual item
Using the formula $Z = \frac{X - \mu}{\sigma}$, where $X = 3$, $\mu = 3.6$, and $\sigma = 1.2$, we find that $Z = -0.5$.
Final Answer:
The probability that the variable exceeds 3 is approximately 0.691.