Questions: Reasoning (31005)
covers Units 1, 2, 3
Question 6 of 23
Find set A′ ∩ B′
U=1,2,3,4,5,6,7
A=1,3,5,7
B=2,5,7
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. A′ ∩ B′= (Use a comma to separate answers as needed.)
B. A′ ∩ B′ is the empty set.
Transcript text: Reasoning (31005)
overs Units 1, 2, \& 3
Question 6 of 23
Find $\operatorname{set} \mathrm{A}^{\prime} \cap \mathrm{B}^{\prime}$
\[
\begin{array}{l}
\mathrm{U}=\{1,2,3,4,5,6,7\} \\
\mathrm{A}=\{1,3,5,7\} \\
\mathrm{B}=\{2,5,7\}
\end{array}
\]
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. $A^{\prime} \cap B^{\prime}=\{$ $\square$ (Use a comma to separate answers as needed.)
B. $A^{\prime} \cap B^{\prime}$ is the empty set.
Solution
Solution Steps
To find \( A' \cap B' \), we need to determine the complements of sets \( A \) and \( B \) with respect to the universal set \( U \), and then find their intersection.
Find \( A' \): The complement of \( A \) is the set of elements in \( U \) that are not in \( A \).
Find \( B' \): The complement of \( B \) is the set of elements in \( U \) that are not in \( B \).
Find \( A' \cap B' \): The intersection of the complements \( A' \) and \( B' \) is the set of elements that are in both \( A' \) and \( B' \).
Step 1: Find the Complements
To find the complements of sets \( A \) and \( B \) with respect to the universal set \( U \):
The universal set is \( U = \{1, 2, 3, 4, 5, 6, 7\} \).
The set \( A = \{1, 3, 5, 7\} \) has a complement \( A' = U - A = \{2, 4, 6\} \).
The set \( B = \{2, 5, 7\} \) has a complement \( B' = U - B = \{1, 3, 4, 6\} \).
Step 2: Find the Intersection of Complements
Next, we find the intersection of the complements \( A' \) and \( B' \):
\[
A' \cap B' = \{2, 4, 6\} \cap \{1, 3, 4, 6\} = \{4, 6\}
\]