Questions: p(x) = (csc x tan x + e^x) / (x^2 sec x)

p(x) = (csc x tan x + e^x) / (x^2 sec x)
Transcript text: $p(x)=\frac{\csc x \tan x+e^{x}}{x^{2} \sec x}$
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Solution

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Solution Steps

To solve for \( p(x) \), we need to simplify the given expression. We will break down the trigonometric and exponential functions and then combine them according to the given formula.

  1. Simplify the trigonometric functions: \(\csc x\), \(\tan x\), and \(\sec x\).
  2. Substitute these simplified forms into the given expression.
  3. Perform the division and simplification.
Step 1: Define the Expression

We start with the expression for \( p(x) \): \[ p(x) = \frac{\csc x \tan x + e^{x}}{x^{2} \sec x} \]

Step 2: Simplify Trigonometric Functions

Using the identities: \[ \csc x = \frac{1}{\sin x}, \quad \tan x = \frac{\sin x}{\cos x}, \quad \sec x = \frac{1}{\cos x} \] we can rewrite the expression as: \[ p(x) = \frac{\frac{1}{\sin x} \cdot \frac{\sin x}{\cos x} + e^{x}}{x^{2} \cdot \frac{1}{\cos x}} = \frac{\frac{1}{\cos x} + e^{x}}{x^{2} \cdot \frac{1}{\cos x}} \]

Step 3: Combine and Simplify

This simplifies to: \[ p(x) = \frac{e^{x} + 1}{x^{2}} \]

Final Answer

Thus, the simplified expression for \( p(x) \) is: \[ \boxed{p(x) = \frac{e^{x} + 1}{x^{2}}} \]

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