Questions: p(x) = (csc x tan x + e^x) / (x^2 sec x)
Transcript text: $p(x)=\frac{\csc x \tan x+e^{x}}{x^{2} \sec x}$
Solution
Solution Steps
To solve for \( p(x) \), we need to simplify the given expression. We will break down the trigonometric and exponential functions and then combine them according to the given formula.
Simplify the trigonometric functions: \(\csc x\), \(\tan x\), and \(\sec x\).
Substitute these simplified forms into the given expression.
Perform the division and simplification.
Step 1: Define the Expression
We start with the expression for \( p(x) \):
\[
p(x) = \frac{\csc x \tan x + e^{x}}{x^{2} \sec x}
\]
Step 2: Simplify Trigonometric Functions
Using the identities:
\[
\csc x = \frac{1}{\sin x}, \quad \tan x = \frac{\sin x}{\cos x}, \quad \sec x = \frac{1}{\cos x}
\]
we can rewrite the expression as:
\[
p(x) = \frac{\frac{1}{\sin x} \cdot \frac{\sin x}{\cos x} + e^{x}}{x^{2} \cdot \frac{1}{\cos x}} = \frac{\frac{1}{\cos x} + e^{x}}{x^{2} \cdot \frac{1}{\cos x}}
\]
Step 3: Combine and Simplify
This simplifies to:
\[
p(x) = \frac{e^{x} + 1}{x^{2}}
\]
Final Answer
Thus, the simplified expression for \( p(x) \) is:
\[
\boxed{p(x) = \frac{e^{x} + 1}{x^{2}}}
\]