Questions: Using Gauss-Jordan elimination to solve the system x-y+z=-5, 3x+y-4z=15, 4x-5y+8z=-32 , the matrix obtained is [ 1 0 0 1; 0 1 0 4; 0 0 1 -2 ]. Complete the following sentence. The system's solution set is ( 1, 4, -2 ) .
Transcript text: Using Gauss-Jordan elimination to solve the system $\left\{\begin{array}{r}x-y+z=-5 \\ 3 x+y-4 z=15 \\ 4 x-5 y+8 z=-32\end{array}\right.$, the matrix obtained is $\left[\begin{array}{rrr|r}1 & 0 & 0 & 1 \\ 0 & 1 & 0 & 4 \\ 0 & 0 & 1 & -2\end{array}\right]$. Complete the following sentence.
The system's solution set is $\qquad$ .
The system's solution set is \{ $\square$ . $\square$. $\square$ ) \}. (Type an ordered triple.)
Solution
Solution Steps
To solve the system of equations using Gauss-Jordan elimination, we first convert the system into an augmented matrix. Then, we perform row operations to transform the matrix into reduced row-echelon form (RREF). The RREF matrix directly gives us the solutions for the variables. In this case, the RREF matrix is already provided, so we can directly read off the solutions for \(x\), \(y\), and \(z\).
Step 1: Write the System of Equations
The given system of equations is:
\[
\begin{align*}
& \quad x - y + z = -5 \\
& \quad 3x + y - 4z = 15 \\
& \quad 4x - 5y + 8z = -32
\end{align*}
\]
Step 2: Convert to Augmented Matrix
The augmented matrix corresponding to the system is:
\[
\left[\begin{array}{rrr|r}
1 & -1 & 1 & -5 \\
3 & 1 & -4 & 15 \\
4 & -5 & 8 & -32
\end{array}\right]
\]
Step 3: Perform Gauss-Jordan Elimination
After applying Gauss-Jordan elimination, we arrive at the reduced row-echelon form (RREF):
\[
\left[\begin{array}{rrr|r}
1 & 0 & 0 & 1 \\
0 & 1 & 0 & 4 \\
0 & 0 & 1 & -2
\end{array}\right]
\]
Step 4: Extract Solutions
From the RREF matrix, we can directly read the solutions:
\[
\begin{align_}
x & = 1 \\
y & = 4 \\
z & = -2
\end{align_}
\]
Final Answer
The system's solution set is \(\boxed{(1, 4, -2)}\).