Questions: Decide whether or not the ordered pair (-6,-6) is a solution of the system: 3x+y=-12 2x+3y=6 Select one: A. No B. Yes

Decide whether or not the ordered pair (-6,-6) is a solution of the system:
3x+y=-12
2x+3y=6

Select one:
A. No
B. Yes
Transcript text: Decide whether or not the ordered pair $(-6,-6)$ is a solution of the system: \[ \begin{array}{l} 3 x+y=-12 \\ 2 x+3 y=6 \end{array} \] Select one: A. No B. Yes
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Solution

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Solution Steps

To determine if the ordered pair \((-6, -6)\) is a solution to the system of equations, substitute \(x = -6\) and \(y = -6\) into both equations. Check if both equations are satisfied with these values. If both equations hold true, then the ordered pair is a solution; otherwise, it is not.

Step 1: Substitute the Ordered Pair into the First Equation

Substitute \(x = -6\) and \(y = -6\) into the first equation \(3x + y = -12\):

\[ 3(-6) + (-6) = -18 - 6 = -24 \]

Since \(-24 \neq -12\), the ordered pair \((-6, -6)\) does not satisfy the first equation.

Step 2: Substitute the Ordered Pair into the Second Equation

Substitute \(x = -6\) and \(y = -6\) into the second equation \(2x + 3y = 6\):

\[ 2(-6) + 3(-6) = -12 - 18 = -30 \]

Since \(-30 \neq 6\), the ordered pair \((-6, -6)\) does not satisfy the second equation.

Final Answer

Since the ordered pair \((-6, -6)\) does not satisfy either of the equations, it is not a solution to the system. Therefore, the answer is \(\boxed{\text{A. No}}\).

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