The completed table is:
\[
\begin{array}{|c|c|c|c|c|c|c|c|}
\hline
x & -5 & -4 & -3 & -2 & -1 & 0 & 1 \\
\hline
y & -8 & -3 & 0 & 1 & 0 & -3 & -8 \\
\hline
\end{array}
\]
The \(x\)-intercepts are \(x = -3\) and \(x = -1\).
Thus, the final answer is:
\(\boxed{x = -3, -1}\)