Questions: Consider the following reaction at 25.00 °C: Mg(OH)2(s) ⇌ Mg2+(aq) + 2 OH-(aq) Calculate ΔG^0 for the reaction. Be sure your answer has the correct number of significant digits.

Consider the following reaction at 25.00 °C:
Mg(OH)2(s) ⇌ Mg2+(aq) + 2 OH-(aq)

Calculate ΔG^0 for the reaction. Be sure your answer has the correct number of significant digits.
Transcript text: Consider the following reaction at $25.00{ }^{\circ} \mathrm{C}$ : \[ \mathrm{Mg}(\mathrm{OH})_{2}(s) \rightleftharpoons \mathrm{Mg}^{2+}(a q)+2 \mathrm{OH}^{-}(a q) \] Calculate $\Delta G^{0}$ for the reaction. Be sure your answer has the correct number of significant digits.
failed

Solution

failed
failed

Solution Steps

Step 1: Identify the Standard Gibbs Free Energy Change Formula

The standard Gibbs free energy change (\(\Delta G^{0}\)) for a reaction can be calculated using the standard Gibbs free energies of formation (\(\Delta G_f^{0}\)) of the reactants and products. The formula is:

\[ \Delta G^{0} = \sum \Delta G_f^{0}(\text{products}) - \sum \Delta G_f^{0}(\text{reactants}) \]

Step 2: Gather Standard Gibbs Free Energies of Formation

We need the standard Gibbs free energies of formation for each species involved in the reaction:

\[ \mathrm{Mg(OH)_2(s)}, \quad \mathrm{Mg^{2+}(aq)}, \quad \text{and} \quad \mathrm{OH^{-}(aq)} \]

From standard tables, we have:

  • \(\Delta G_f^{0}(\mathrm{Mg(OH)_2(s)}) = -833.6 \, \text{kJ/mol}\)
  • \(\Delta G_f^{0}(\mathrm{Mg^{2+}(aq)}) = -454.8 \, \text{kJ/mol}\)
  • \(\Delta G_f^{0}(\mathrm{OH^{-}(aq)}) = -157.2 \, \text{kJ/mol}\)
Step 3: Apply the Gibbs Free Energy Change Formula

Substitute the values into the formula:

\[ \Delta G^{0} = [\Delta G_f^{0}(\mathrm{Mg^{2+}(aq)}) + 2 \cdot \Delta G_f^{0}(\mathrm{OH^{-}(aq)})] - \Delta G_f^{0}(\mathrm{Mg(OH)_2(s)}) \]

\[ \Delta G^{0} = [-454.8 + 2 \cdot (-157.2)] - (-833.6) \]

Step 4: Perform the Calculation

Calculate the values inside the brackets first:

\[ \Delta G^{0} = [-454.8 + (-314.4)] - (-833.6) \]

\[ \Delta G^{0} = -769.2 - (-833.6) \]

\[ \Delta G^{0} = -769.2 + 833.6 \]

\[ \Delta G^{0} = 64.4 \, \text{kJ/mol} \]

Final Answer

\(\boxed{\Delta G^{0} = 64.4 \, \text{kJ/mol}}\)

Was this solution helpful?
failed
Unhelpful
failed
Helpful