Questions: The osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant R. Suppose the osmotic pressure of a certain solution is measured to be 12 atm at an absolute temperature of 309 K.
Write an equation that will let you calculate the molarity c of this solution. Your equation should contain only symbols. Be sure you define each symbol other than R.
Your equation:
Definitions of your symbols:
=12 atm
=309 K
Transcript text: The osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant $R$. Suppose the osmotic pressure of a certain solution is measured to be 12. atm at an absolute temperature of $309 . \mathrm{K}$.
Write an equation that will let you calculate the molarity $c$ of this solution. Your equation should contain only symbols. Be sure you define each symbol other than $R$.
Your equation:
Definitions of your symbols:
$\square=12 . \mathrm{atm}$
$\square=309 . \mathrm{K}$
Solution
Solution Steps
Step 1: Understanding the Osmotic Pressure Equation
The osmotic pressure (\(\Pi\)) of a solution is given by the equation:
\[
\Pi = cRT
\]
where:
\(\Pi\) is the osmotic pressure,
\(c\) is the molarity of the solution,
\(R\) is the gas constant,
\(T\) is the absolute temperature in Kelvin.
Step 2: Rearranging the Equation to Solve for Molarity
To find the molarity \(c\), we rearrange the equation:
\[
c = \frac{\Pi}{RT}
\]
Step 3: Defining the Symbols
We need to define the symbols used in the equation:
\(\Pi = 12 \, \text{atm}\) (osmotic pressure),
\(T = 309 \, \text{K}\) (absolute temperature).
Final Answer
\[
\boxed{c = \frac{\Pi}{RT}}
\]
Definitions of symbols: