Questions: Fill in the missing information:
symbol atom or ion? check all that apply number of protons number of electrons
Al^2+ neutral atom cation anion
neutral atom cation anion 33 33
neutral atom cation anion 53 54
Transcript text: Fill in the missing information:
\begin{tabular}{|c|c|c|c|}
\hline symbol & atom or ion? check all that apply & number of protons & number of electrons \\
\hline $\mathrm{Al}^{2+}$ & $\square$ neutral atom cation anion & $\square$ & $\square$ \\
\hline $\square$ & $\square$ neutral atom $\square$ cation anion & 33 & 33 \\
\hline $\square$ & $\square$ neutral atom $\square$ cation anion & 53 & 54 \\
\hline
\end{tabular}
Solution
Solution Steps
Step 1: Determine the missing information for \(\mathrm{Al}^{2+}\)
\(\mathrm{Al}^{2+}\) is a cation.
Aluminum (Al) has 13 protons.
As a \(2+\) cation, it has lost 2 electrons, so it has \(13 - 2 = 11\) electrons.
Step 2: Determine the symbol for the atom with 33 protons and 33 electrons
An atom with 33 protons is arsenic (As).
Since it has an equal number of protons and electrons, it is a neutral atom.
Step 3: Determine the symbol for the ion with 53 protons and 54 electrons
An atom with 53 protons is iodine (I).
Since it has one more electron than protons, it is an anion with a \(1-\) charge, denoted as \(\mathrm{I}^{-}\).
Step 4: Fill in the table
\[
\begin{tabular}{|c|c|c|c|}
\hline
symbol & atom or ion? check all that apply & number of protons & number of electrons \\
\hline
\mathrm{Al}^{2+} & \text{cation} & 13 & 11 \\
\hline
\mathrm{As} & \text{neutral atom} & 33 & 33 \\
\hline
\mathrm{I}^{-} & \text{anion} & 53 & 54 \\
\hline
\end{tabular}
\]