Questions: Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is shown in the table below. Lengths (mm) Frequency ------ 160-169 1 170-179 16 180-189 71 190-199 108 200-209 83 210-219 18 220-229 3 What is the class midpoint for the second class? class midpoint =

Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is shown in the table below.

Lengths (mm)  Frequency
------
160-169  1
170-179  16
180-189  71
190-199  108
200-209  83
210-219  18
220-229  3

What is the class midpoint for the second class?
class midpoint =
Transcript text: 9:56 AM Fri Jan 17 8 myopenmath.com Review for Major Quiz 1 Progress saved Done Score: 21.38/52 Answered: 22/52 Question 23 $0 / 1$ pt Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm the GFDT below. \begin{tabular}{|c|c|} \hline Lengths $(\mathrm{mm})$ & Frequency \\ \hline $160-169$ & 1 \\ \hline $170-179$ & 16 \\ \hline $180-189$ & 71 \\ \hline $190-199$ & 108 \\ \hline $200-209$ & 83 \\ \hline $210-219$ & 18 \\ \hline $220-229$ & 3 \\ \hline \end{tabular} What is the class midpoint for the second class? class midpoint $=$ $\square$ Submit Question
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Solution

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Solution Steps

Step 1: Identify the second class

The second class in the GFDT is \(170-179\).

Step 2: Calculate the class midpoint

The class midpoint is calculated using the formula: \[ \text{Midpoint} = \frac{\text{Lower Bound} + \text{Upper Bound}}{2} \] For the second class \(170-179\): \[ \text{Midpoint} = \frac{170 + 179}{2} = \frac{349}{2} = 174.5 \]

Step 3: Present the result

The class midpoint for the second class is \(174.5\).

Final Answer

\(\boxed{174.5}\)

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