Questions: Write the standard form of the equation and the general form of the equation of the circle with radius r and center (n, x).
Then graph the circle
r=2; (x)=(-2,0)
The standard form of the equation of this circle is (x-2)^2+(y+2)^2
Transcript text: Write the standard form of the equation and the general form of the equation of the circle with radius $r$ and center $(n, x)$.
Then graph the circle
$r=2 ; \quad(x)=(-2,0)$
The standard form of the equation of this circle is $(x-2)^{2}+(y+2)^{2}$
Solution
Solution Steps
Step 1: Identify the Circle's Parameters
The circle has a radius \( r = 2 \) and a center at \( (-2, 0) \).
Step 2: Write the Standard Form of the Circle's Equation
The standard form of the equation of a circle with center \((h, k)\) and radius \(r\) is:
\[
(x - h)^2 + (y - k)^2 = r^2
\]
Substituting the given values, \( h = -2 \), \( k = 0 \), and \( r = 2 \), we get:
\[
(x + 2)^2 + (y - 0)^2 = 2^2
\]
\[
(x + 2)^2 + y^2 = 4
\]
Step 3: Write the General Form of the Circle's Equation
The general form of the equation of a circle is:
\[
x^2 + y^2 + Dx + Ey + F = 0
\]
Expanding the standard form:
\[
(x + 2)^2 + y^2 = 4
\]
\[
x^2 + 4x + 4 + y^2 = 4
\]
Subtract 4 from both sides:
\[
x^2 + y^2 + 4x = 0
\]
Thus, the general form is:
\[
x^2 + y^2 + 4x = 0
\]