Questions: A sample of 36 cans of regular Coke produced a mean weight of 0.8168 pounds. A sample of 36 cans of regular Pepsi produced a mean weight of 0.8241 pounds. Coca-Cola reports that standard deviation for the weight of all cans of regular Coke is known to be 0.0075 pounds and Pepsi-Co reports that the standard deviation for the weight of all cans of regular Pepsi is known to be 0.0057 pounds. Construct a 99% confidence interval for the difference between the mean weights of regular Coke and regular Pepsi.
Transcript text: 12. A sample of 36 cans of regular Coke produced a mean weight of 0.8168 pounds. A sample of 36 cans of regular Pepsi produced a mean weight of 0.8241 pounds. Coca-Cola reports that standard deviation for the weight of all cans of regular Coke is known to be 0.0075 pounds and Pepsi-Co reports that the standard deviation for the weight of all cans of regular Pepsi is known to be 0.0057 pounds. Construct a 99\% confidence interval for the difference between the mean weights of regular Coke and regular Pepsi.
Solution
Solution Steps
Step 1: Given Data
We have the following data for the two samples:
For regular Coke:
Sample mean (\(\bar{x}_1\)) = 0.8168 pounds
Sample size (\(n_1\)) = 36
Population standard deviation (\(\sigma_1\)) = 0.0075 pounds
For regular Pepsi:
Sample mean (\(\bar{x}_2\)) = 0.8241 pounds
Sample size (\(n_2\)) = 36
Population standard deviation (\(\sigma_2\)) = 0.0057 pounds
Step 2: Confidence Level
We are constructing a 99% confidence interval, which corresponds to a significance level (\(\alpha\)) of:
\[
\alpha = 1 - 0.99 = 0.01
\]
Step 3: Calculate the Confidence Interval
The formula for the confidence interval for the difference between two population means with known variances is given by:
\[
(\bar{x}_1 - \bar{x}_2) \pm z \sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}
\]
Where \(z\) is the z-score corresponding to the desired confidence level. For a 99% confidence level, \(z \approx 2.5758\).
Now, we can calculate the confidence interval:
\[
-0.0073 \pm 2.5758 \cdot 0.00157
\]
Calculating the margin of error:
\[
\text{Margin of Error} \approx 2.5758 \cdot 0.00157 \approx 0.00405
\]
Thus, the confidence interval is:
\[
(-0.0073 - 0.00405, -0.0073 + 0.00405) = (-0.01135, -0.00325)
\]
Step 4: Final Result
The 99% confidence interval for the difference between the mean weights of regular Coke and regular Pepsi is:
\[
(-0.0113, -0.0033)
\]