Questions: Write and balance the equation for the complete combustion of acetylene, C2H2. Phase symbols and energy changes 등 are optional.
Transcript text: Write and balance the equation for the complete combustion of acetylene, $\mathrm{C}_{2} \mathrm{H}_{2}$. Phase symbols and energy changes 등 are optional.
Solution
Solution Steps
Step 1: Identify the Reactants and Products
The complete combustion of acetylene (\(\mathrm{C}_2\mathrm{H}_2\)) involves reacting it with oxygen (\(\mathrm{O}_2\)) to produce carbon dioxide (\(\mathrm{CO}_2\)) and water (\(\mathrm{H}_2\mathrm{O}\)).
Step 2: Write the Unbalanced Chemical Equation
The unbalanced chemical equation for the combustion of acetylene is:
\[
\mathrm{C}_2\mathrm{H}_2 + \mathrm{O}_2 \rightarrow \mathrm{CO}_2 + \mathrm{H}_2\mathrm{O}
\]
Step 3: Balance the Chemical Equation
Balance Carbon Atoms: There are 2 carbon atoms in \(\mathrm{C}_2\mathrm{H}_2\), so we need 2 \(\mathrm{CO}_2\) molecules:
\[
\mathrm{C}_2\mathrm{H}_2 + \mathrm{O}_2 \rightarrow 2\mathrm{CO}_2 + \mathrm{H}_2\mathrm{O}
\]
Balance Hydrogen Atoms: There are 2 hydrogen atoms in \(\mathrm{C}_2\mathrm{H}_2\), so we need 1 \(\mathrm{H}_2\mathrm{O}\) molecule:
\[
\mathrm{C}_2\mathrm{H}_2 + \mathrm{O}_2 \rightarrow 2\mathrm{CO}_2 + \mathrm{H}_2\mathrm{O}
\]
Balance Oxygen Atoms: There are 4 oxygen atoms in 2 \(\mathrm{CO}_2\) and 1 oxygen atom in \(\mathrm{H}_2\mathrm{O}\), totaling 5 oxygen atoms. Therefore, we need \(\frac{5}{2}\) \(\mathrm{O}_2\) molecules:
\[
\mathrm{C}_2\mathrm{H}_2 + \frac{5}{2}\mathrm{O}_2 \rightarrow 2\mathrm{CO}_2 + \mathrm{H}_2\mathrm{O}
\]
Clear Fraction by Multiplying Through by 2: To eliminate the fraction, multiply the entire equation by 2:
\[
2\mathrm{C}_2\mathrm{H}_2 + 5\mathrm{O}_2 \rightarrow 4\mathrm{CO}_2 + 2\mathrm{H}_2\mathrm{O}
\]
Final Answer
The balanced chemical equation for the complete combustion of acetylene is:
\[
\boxed{2\mathrm{C}_2\mathrm{H}_2 + 5\mathrm{O}_2 \rightarrow 4\mathrm{CO}_2 + 2\mathrm{H}_2\mathrm{O}}
\]