Questions: CONNECTING CONCEPTS The measure of an angle is 6° less than the measure of its complement. Identify and solve an algebraic equation.
x+(x+6)=90
x+(x-6)=90
x+(x+6)=180
x+(x-6)=180
Find the measure of each angle.
Transcript text: CONNECTING CONCEPTS The measure of an angle is $6^{\circ}$ less than the measure of its complement. Identify and solve an algebraic equation.
$x+(x+6)=90$
$x+(x-6)=90$
$x+(x+6)=180$
$x+(x-6)=180$
Find the measure of each angle.
Solution
Solution Steps
To solve the problem, we need to identify the correct algebraic equation that represents the relationship between the angle and its complement. The complement of an angle is defined as the angle that, when added to the original angle, equals $90^{\circ}$. We are given that the measure of the angle is $6^{\circ}$ less than its complement. Therefore, we need to solve the equation $x + (x + 6) = 90$.
We are given that the measure of an angle is \(6^\circ\) less than the measure of its complement. The complement of an angle \(x\) is \(90^\circ - x\). Therefore, the correct equation is:
\[ x + (x + 6) = 90 \]
Step 2: Simplify and Solve the Equation
Simplify the equation:
\[ x + x + 6 = 90 \]
\[ 2x + 6 = 90 \]
Subtract 6 from both sides:
\[ 2x = 84 \]
Divide by 2:
\[ x = 42 \]
Step 3: Calculate the Measure of Each Angle
The measure of the first angle is:
\[ x = 42^\circ \]
The measure of the second angle, which is \(6^\circ\) more than the first angle, is:
\[ x + 6 = 42 + 6 = 48^\circ \]