Questions: Solubility is the concentration of unsaturated ions in solution.
Ksp is the same as the solubility.
Ksp is an equilibrium constant and solubility is the concentration of a saturated solution.
Ksp is the solubility product constant for a precipitate.
Solubility = Kw times Ksp.
Transcript text: Solubility is the concentration of unsaturated ions in solution.
$K_{\text {sp }}$ is the same as the solubility.
$K_{\mathrm{sp}}$ is an equilibrium constant and solubility is the concentration of a saturated solution.
$K_{\text {sp }}$ is the solubility product constant for a precipitate.
Solubility $=K_{\mathrm{w}} \times K_{\text {sp }}$.
Solution
Solution Steps
Step 1: Understanding Solubility
Solubility refers to the concentration of a solute that can dissolve in a solvent to form a saturated solution at a given temperature. It is typically expressed in terms of molarity (moles per liter).
Step 2: Understanding \( K_{\text{sp}} \)
\( K_{\text{sp}} \) is the solubility product constant, which is an equilibrium constant for the dissolution of a sparingly soluble ionic compound. It represents the product of the molar concentrations of the constituent ions, each raised to the power of their stoichiometric coefficients.
Step 3: Clarifying the Statements
"Solubility is the concentration of unsaturated ions in solution." - This is incorrect. Solubility refers to the concentration of ions in a saturated solution.
"$K_{\text{sp}}$ is the same as the solubility." - This is incorrect. \( K_{\text{sp}} \) is the solubility product constant, not the solubility itself.
"$K_{\mathrm{sp}}$ is an equilibrium constant and solubility is the concentration of a saturated solution." - This is correct. \( K_{\text{sp}} \) is indeed an equilibrium constant, and solubility is the concentration of a saturated solution.
"$K_{\text{sp}}$ is the solubility product constant for a precipitate." - This is correct. \( K_{\text{sp}} \) is the solubility product constant for a sparingly soluble precipitate.
"Solubility \(= K_{\mathrm{w}} \times K_{\text{sp}}\)." - This is incorrect. Solubility is not directly related to \( K_{\mathrm{w}} \) (the ion-product constant for water) and \( K_{\text{sp}} \) in this manner.
Final Answer
\[
\boxed{\text{3. } K_{\mathrm{sp}} \text{ is an equilibrium constant and solubility is the concentration of a saturated solution.}}
\]
\[
\boxed{\text{4. } K_{\text{sp}} \text{ is the solubility product constant for a precipitate.}}
\]