Questions: Give the systematic name for the following:
Part 1 of 2
CuF=
Part 2 of 2
Fe2 S3=
Transcript text: Give the systematic name for the following:
Part 1 of 2
\[
\mathrm{CuF}=
\]
$\square$
Part 2 of 2
\[
\mathrm{Fe}_{2} \mathrm{~S}_{3}=
\]
$\square$
Solution
Solution Steps
Step 1: Identify the elements and their oxidation states
For \(\mathrm{CuF}\):
Copper (Cu) can have oxidation states of +1 or +2.
Fluorine (F) has an oxidation state of -1.
Step 2: Determine the correct oxidation state for copper
Since there is only one fluorine atom, the oxidation state of copper must be +1 to balance the -1 charge of fluorine.
Step 3: Write the systematic name for \(\mathrm{CuF}\)
The systematic name is Copper(I) fluoride.
Step 4: Identify the elements and their oxidation states
For \(\mathrm{Fe}_{2} \mathrm{~S}_{3}\):
Iron (Fe) can have oxidation states of +2 or +3.
Sulfur (S) has an oxidation state of -2.
Step 5: Determine the correct oxidation state for iron
There are 3 sulfur atoms, each with a -2 charge, giving a total of -6.
To balance this, the 2 iron atoms must have a total charge of +6, so each iron atom has an oxidation state of +3.
Step 6: Write the systematic name for \(\mathrm{Fe}_{2} \mathrm{~S}_{3}\)
The systematic name is Iron(III) sulfide.
Final Answer
For Part 1: \( \boxed{\text{Copper(I) fluoride}} \)
For Part 2: \( \boxed{\text{Iron(III) sulfide}} \)