We start with the equation
\[ x^{2} = 5x + 14 \]
To bring all terms to one side, we rearrange it to the standard polynomial form:
\[ x^{2} - 5x - 14 = 0 \]
Next, we factor the polynomial \( x^{2} - 5x - 14 \). The factorization yields:
\[ (x - 7)(x + 2) = 0 \]
To find the roots of the equation, we set each factor equal to zero:
Thus, the solutions to the equation \( x^{2} = 5x + 14 \) are \( x = 7 \) and \( x = -2 \).
\(\boxed{x = 7}\) and \(\boxed{x = -2}\)
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