Questions: Find f(a), f(a+h), and the difference quotient (f(a+h)-f(a))/h, where h ≠ 0. f(x)=x/(x+2) f(a)= f(a+h)= (f(a+h)-f(a))/h=

Find f(a), f(a+h), and the difference quotient (f(a+h)-f(a))/h, where h ≠ 0.

f(x)=x/(x+2)
f(a)=
f(a+h)=
(f(a+h)-f(a))/h=
Transcript text: Find $f(a), f(a+h)$, and the difference quotient $\frac{f(a+h)-f(a)}{h}$, where $h \neq 0$. \[ \begin{array}{c} f(x)=\frac{x}{x+2} \\ f(a)=\square \\ f(a+h)=\square \\ \frac{f(a+h)-f(a)}{h}=\square \end{array} \] Need Help? Read It Watch it
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Solution

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Solution Steps

To solve this problem, we need to evaluate the function f(x)=xx+2 f(x) = \frac{x}{x+2} at specific points and then compute the difference quotient. First, substitute a a into the function to find f(a) f(a) . Next, substitute a+h a+h into the function to find f(a+h) f(a+h) . Finally, use these results to calculate the difference quotient f(a+h)f(a)h\frac{f(a+h)-f(a)}{h}.

Step 1: Evaluate f(a) f(a)

To find f(a) f(a) , substitute a a into the function f(x)=xx+2 f(x) = \frac{x}{x+2} . This gives: f(a)=aa+2 f(a) = \frac{a}{a+2}

Step 2: Evaluate f(a+h) f(a+h)

To find f(a+h) f(a+h) , substitute a+h a+h into the function: f(a+h)=a+ha+h+2 f(a+h) = \frac{a+h}{a+h+2}

Step 3: Calculate the Difference Quotient

The difference quotient is given by: f(a+h)f(a)h=a+ha+h+2aa+2h \frac{f(a+h) - f(a)}{h} = \frac{\frac{a+h}{a+h+2} - \frac{a}{a+2}}{h} Simplifying this expression, we find: f(a+h)f(a)h=2a2+ah+4a+2h+4 \frac{f(a+h) - f(a)}{h} = \frac{2}{a^2 + ah + 4a + 2h + 4}

Final Answer

The values are:

  • f(a)=aa+2 f(a) = \frac{a}{a+2}
  • f(a+h)=a+ha+h+2 f(a+h) = \frac{a+h}{a+h+2}
  • The difference quotient is 2a2+ah+4a+2h+4\boxed{\frac{2}{a^2 + ah + 4a + 2h + 4}}
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