Questions: Find f(a), f(a+h), and the difference quotient (f(a+h)-f(a))/h, where h ≠ 0. f(x)=x/(x+2) f(a)= f(a+h)= (f(a+h)-f(a))/h=

Find f(a), f(a+h), and the difference quotient (f(a+h)-f(a))/h, where h ≠ 0.

f(x)=x/(x+2)
f(a)=
f(a+h)=
(f(a+h)-f(a))/h=
Transcript text: Find $f(a), f(a+h)$, and the difference quotient $\frac{f(a+h)-f(a)}{h}$, where $h \neq 0$. \[ \begin{array}{c} f(x)=\frac{x}{x+2} \\ f(a)=\square \\ f(a+h)=\square \\ \frac{f(a+h)-f(a)}{h}=\square \end{array} \] Need Help? Read It Watch it
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Solution

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Solution Steps

To solve this problem, we need to evaluate the function \( f(x) = \frac{x}{x+2} \) at specific points and then compute the difference quotient. First, substitute \( a \) into the function to find \( f(a) \). Next, substitute \( a+h \) into the function to find \( f(a+h) \). Finally, use these results to calculate the difference quotient \(\frac{f(a+h)-f(a)}{h}\).

Step 1: Evaluate \( f(a) \)

To find \( f(a) \), substitute \( a \) into the function \( f(x) = \frac{x}{x+2} \). This gives: \[ f(a) = \frac{a}{a+2} \]

Step 2: Evaluate \( f(a+h) \)

To find \( f(a+h) \), substitute \( a+h \) into the function: \[ f(a+h) = \frac{a+h}{a+h+2} \]

Step 3: Calculate the Difference Quotient

The difference quotient is given by: \[ \frac{f(a+h) - f(a)}{h} = \frac{\frac{a+h}{a+h+2} - \frac{a}{a+2}}{h} \] Simplifying this expression, we find: \[ \frac{f(a+h) - f(a)}{h} = \frac{2}{a^2 + ah + 4a + 2h + 4} \]

Final Answer

The values are:

  • \( f(a) = \frac{a}{a+2} \)
  • \( f(a+h) = \frac{a+h}{a+h+2} \)
  • The difference quotient is \(\boxed{\frac{2}{a^2 + ah + 4a + 2h + 4}}\)
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