Questions: A die is rolled. Find the probability of the given event. (a) The number showing is a 4 ; The probability is : (b) The number showing is an even number; The probability is : (c) The number showing is greater than 4 ; The probability is :

A die is rolled. Find the probability of the given event.
(a) The number showing is a 4 ;

The probability is : 
(b) The number showing is an even number;

The probability is : 
(c) The number showing is greater than 4 ;

The probability is :
Transcript text: A die is rolled. Find the probability of the given event. (a) The number showing is a 4 ; The probability is : $\square$ (b) The number showing is an even number; The probability is : $\square$ (c) The number showing is greater than 4 ; The probability is : $\square$
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Solution

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Solution Steps

Step 1: Determine the total number of possible outcomes

A standard die has 6 faces, numbered from 1 to 6. Therefore, the total number of possible outcomes when rolling the die is \( 6 \).

Step 2: Calculate the probability of rolling a 4

There is only 1 favorable outcome for rolling a 4. The probability \( P \) of rolling a 4 is given by: \[ P(\text{4}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{1}{6} \]

Step 3: Calculate the probability of rolling an even number

The even numbers on a die are 2, 4, and 6. There are 3 favorable outcomes. The probability \( P \) of rolling an even number is: \[ P(\text{Even}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{3}{6} = \frac{1}{2} \]

Step 4: Calculate the probability of rolling a number greater than 4

The numbers greater than 4 on a die are 5 and 6. There are 2 favorable outcomes. The probability \( P \) of rolling a number greater than 4 is: \[ P(\text{Greater than 4}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{2}{6} = \frac{1}{3} \]

Final Answer

(a) The probability is: \( \boxed{\frac{1}{6}} \)

(b) The probability is: \( \boxed{\frac{1}{2}} \)

(c) The probability is: \( \boxed{\frac{1}{3}} \)

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