Questions: If z is a standard normal variable, find the probability that z lies between -2.41 and 0. Round to four decimal places.
A. 0.5080
B. 0.0948
C. 0.4920
D. 0.4910
Transcript text: If $z$ is a standard normal variable, find the probability that $z$ lies between -2.41 and 0 . Round to four decimal places.
A. 0.5080
B. 0.0948
C. 0.4920
D. 0.4910
Solution
Solution Steps
Step 1: Identify the Z-scores
The Z-score for a is -2.41 and for b is 0.
Step 2: Use the Standard Normal Distribution Table
Using the Z-table, we find $P(Z \leq a)$ is approximately 0.008 and $P(Z \leq b)$ is approximately 0.5.
Step 3: Calculate the Desired Probability
The probability that $Z$ lies between -2.41 and 0 is $P(a < Z < b) = P(Z \leq b) - P(Z \leq a) = 0.5 - 0.008 = 0.492$.
Final Answer: The probability that $Z$ lies between -2.41 and 0 is approximately 0.492.