Questions: If z is a standard normal variable, find the probability that z lies between -2.41 and 0. Round to four decimal places. A. 0.5080 B. 0.0948 C. 0.4920 D. 0.4910

Solution Steps

The Z-score for a is -2.41 and for b is 0.

Using the Z-table, we find $P(Z \leq a)$ is approximately 0.008 and $P(Z \leq b)$ is approximately 0.5.

The probability that $Z$ lies between -2.41 and 0 is $P(a < Z < b) = P(Z \leq b) - P(Z \leq a) = 0.5 - 0.008 = 0.492$.

Final Answer: The probability that $Z$ lies between -2.41 and 0 is approximately 0.492.