Questions: Fill in the table using this function rule. f(x) = √x + 2 Simplify your answers as much as possible. Click "Not a real number" if applicable. x f(x) -9 0 9 16

Fill in the table using this function rule.
f(x) = √x + 2

Simplify your answers as much as possible. Click "Not a real number" if applicable.

x  f(x)
-9  
0  
9  
16
Transcript text: Fill in the table using this function rule. \[ f(x)=\sqrt{x}+2 \] Simplify your answers as much as possible. Click "Not a real number" if applicable. \begin{tabular}{|c|c|} \hline$x$ & $f(x)$ \\ \hline-9 & $\square$ \\ \hline 0 & $\square$ \\ \hline 9 & $\square$ \\ \hline 16 & $\square$ \\ \hline \end{tabular}
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Solution

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Solution Steps

To fill in the table using the function rule \( f(x) = \sqrt{x} + 2 \), we need to evaluate the function for each given value of \( x \). If \( x \) is negative, the square root is not a real number. For non-negative values of \( x \), compute the square root and add 2.

Step 1: Evaluate \( f(x) \) for \( x = -9 \)

The function \( f(x) = \sqrt{x} + 2 \) involves taking the square root of \( x \). Since \(-9\) is negative, \(\sqrt{-9}\) is not a real number. Therefore, \( f(-9) \) is not a real number.

Step 2: Evaluate \( f(x) \) for \( x = 0 \)

For \( x = 0 \), we have: \[ f(0) = \sqrt{0} + 2 = 0 + 2 = 2 \]

Step 3: Evaluate \( f(x) \) for \( x = 9 \)

For \( x = 9 \), we have: \[ f(9) = \sqrt{9} + 2 = 3 + 2 = 5 \]

Step 4: Evaluate \( f(x) \) for \( x = 16 \)

For \( x = 16 \), we have: \[ f(16) = \sqrt{16} + 2 = 4 + 2 = 6 \]

Final Answer

  • For \( x = -9 \), \( f(x) \) is not a real number.
  • For \( x = 0 \), \( f(x) = \boxed{2} \).
  • For \( x = 9 \), \( f(x) = \boxed{5} \).
  • For \( x = 16 \), \( f(x) = \boxed{6} \).
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