Questions: Had we compared a series of metal chlorides (NaCl, CaCl2, AlCl3), we would have seen a difference in conductivity values, even though their concentrations are the same ( 0.05 M ): AlCl3 should have the highest conductivity, and NaCl the lowest. To explain, complete the dissociation equations by filling in the missing charges and coefficients. For example: NaCl(aq) → Na+1+Cl-1 would be completed as: NaCl(aq) → 1 Na+1 and 1 Cl-1 CaCl2(aq) → v Ca+v and v Cl-v AlCl3(aq) → v Al+v and v Cl-v

Transcript text: Had we compared a series of metal chlorides $\left(\mathrm{NaCl}, \mathrm{CaCl}_{2}, \mathrm{AlCl}_{3}\right)$, we would have seen a difference in conductivity values, even though their concentrations are the same ( 0.05 M ): $\mathrm{AlCl}_{3}$ should have the highest conductivity, and NaCl the lowest. To explain, complete the dissociation equations by filling in the missing charges and coefficients. For example: $\mathrm{NaCl}(\mathrm{aq}) \rightarrow \mathrm{Na}^{+1}+\mathrm{Cl}^{+1}$ would be completed as: $\mathrm{NaCl}(\mathrm{aq}) \rightarrow$ $1 \mathrm{Na}+1$ and $1 \mathrm{Cl}-1$ \[ \begin{array}{l} \mathrm{CaCl}_{2}(\mathrm{aq}) \rightarrow \hat{v} \mathrm{Ca}^{+} \hat{v} \text { and } \hat{v} \mathrm{Cl}^{-} \hat{v} \\ \mathrm{AlCl}_{3}(\mathrm{aq}) \rightarrow \hat{v} \mathrm{Al}^{+} \hat{v} \text { and } \hat{v} \mathrm{Cl}^{-} \hat{v} \end{array} \]