Questions: The following data represent the daily high temperatures (in degrees Fahrenheit) for the month of June in a town. Complete parts (a) through (c) below. (a) Construct frequency and relative frequency distributions. (Round to the nearest integer as needed)

Solution Steps

The frequency distribution of the daily high temperatures for the month of June is as follows:

\[ \begin{align_} \text{Temperature: } 85 & \quad \text{Frequency: } 8 \\ \text{Temperature: } 87 & \quad \text{Frequency: } 4 \\ \text{Temperature: } 88 & \quad \text{Frequency: } 4 \\ \text{Temperature: } 86 & \quad \text{Frequency: } 4 \\ \text{Temperature: } 89 & \quad \text{Frequency: } 4 \\ \text{Temperature: } 90 & \quad \text{Frequency: } 3 \\ \text{Temperature: } 91 & \quad \text{Frequency: } 3 \\ \end{align_} \]

The relative frequency distribution is calculated by dividing each frequency by the total number of observations, which is \( n = 30 \). The relative frequencies are as follows:

\[ \begin{align_} \text{Temperature: } 85 & \quad \text{Relative Frequency: } \frac{8}{30} = 0.27 \\ \text{Temperature: } 87 & \quad \text{Relative Frequency: } \frac{4}{30} \approx 0.13 \\ \text{Temperature: } 88 & \quad \text{Relative Frequency: } \frac{4}{30} \approx 0.13 \\ \text{Temperature: } 86 & \quad \text{Relative Frequency: } \frac{4}{30} \approx 0.13 \\ \text{Temperature: } 89 & \quad \text{Relative Frequency: } \frac{4}{30} \approx 0.13 \\ \text{Temperature: } 90 & \quad \text{Relative Frequency: } \frac{3}{30} = 0.10 \\ \text{Temperature: } 91 & \quad \text{Relative Frequency: } \frac{3}{30} = 0.10 \\ \end{align_} \]

Final Answer