Questions: Find the exact value of the expression.
tan[sin^(-1)(9/10)]
Select the correct choice and fill in any answer boxes in your choice
A. tan[sin^(-1)(9/10)]= □
(Simplify your answer, including any radicals. Use integers or
B. There is no solution.
Transcript text: Find the exact value of the expression.
\[
\tan \left[\sin ^{-1}\left(\frac{9}{10}\right)\right]
\]
Select the correct choice and fill in any answer boxes in your choice
A. $\tan \left[\sin ^{-1}\left(\frac{9}{10}\right)\right]=$ $\square$
(Simplify your answer, including any radicals. Use integers or
B. There is no solution.
Solution
Solution Steps
To find the exact value of \(\tan \left[\sin ^{-1}\left(\frac{9}{10}\right)\right]\), we can use the following approach:
Recognize that \(\sin^{-1}\left(\frac{9}{10}\right)\) represents an angle \(\theta\) such that \(\sin(\theta) = \frac{9}{10}\).
Use the Pythagorean identity to find \(\cos(\theta)\): \(\cos(\theta) = \sqrt{1 - \sin^2(\theta)}\).
Calculate \(\tan(\theta)\) using the identity \(\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}\).
Step 1: Determine \(\sin(\theta)\)
Given that \(\theta = \sin^{-1}\left(\frac{9}{10}\right)\), we have:
\[
\sin(\theta) = \frac{9}{10} = 0.9
\]
Step 2: Calculate \(\cos(\theta)\)
Using the Pythagorean identity, we find \(\cos(\theta)\):
\[
\cos(\theta) = \sqrt{1 - \sin^2(\theta)} = \sqrt{1 - \left(\frac{9}{10}\right)^2} = \sqrt{1 - \frac{81}{100}} = \sqrt{\frac{19}{100}} = \frac{\sqrt{19}}{10} \approx 0.4359
\]
Step 3: Calculate \(\tan(\theta)\)
Now, we can calculate \(\tan(\theta)\) using the definition:
\[
\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} = \frac{\frac{9}{10}}{\frac{\sqrt{19}}{10}} = \frac{9}{\sqrt{19}} \approx 2.0647
\]
Final Answer
Thus, the exact value of \(\tan \left[\sin^{-1}\left(\frac{9}{10}\right)\right]\) is:
\[
\boxed{\frac{9}{\sqrt{19}}}
\]