Questions: If the DNA analysis of gene shows 23% adenine, what would be the percentage of thymine, cytosine, and guanine. Blank 1: Thymine: Blank 2: Cytosine: Blank 3: Guanine:

If the DNA analysis of gene shows 23% adenine, what would be the percentage of thymine, cytosine, and guanine.

Blank 1: Thymine:  
Blank 2: Cytosine:  
Blank 3: Guanine:
Transcript text: If the DNA analysis of gene shows $23 \%$ adenine, what would be the percentage of thymine, cytosine, and guanine. Blank 1: Thymine: $\qquad$ Blank 2: Cytosine: $\qquad$ Blank 3: Guanine: $\qquad$
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Solution

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To solve this question, we need to apply the basic principles of DNA base pairing. In DNA, adenine (A) pairs with thymine (T), and cytosine (C) pairs with guanine (G). This means that the percentage of adenine in the DNA will be equal to the percentage of thymine, and the percentage of cytosine will be equal to the percentage of guanine.

Given that the DNA analysis shows \(23\%\) adenine, we can deduce the following:

  1. Thymine (T): Since adenine pairs with thymine, the percentage of thymine will also be \(23\%\).

  2. Cytosine (C) and Guanine (G): The total percentage of all four bases in DNA must add up to \(100\%\). Therefore, the combined percentage of cytosine and guanine will be \(100\% - (23\% + 23\%) = 54\%\). Since cytosine pairs with guanine, they will each have half of this remaining percentage.

    • Cytosine: \(54\% / 2 = 27\%\)
    • Guanine: \(54\% / 2 = 27\%\)

Therefore, the percentages are as follows:

Blank 1: Thymine: \(23\%\)
Blank 2: Cytosine: \(27\%\)
Blank 3: Guanine: \(27\%\)

In summary, the answer is:

  • Thymine: \(23\%\)
  • Cytosine: \(27\%\)
  • Guanine: \(27\%\)
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