Transcript text: Evaluate $\int[f(x) \cdot g(x)]^{\prime} d x$
Solution
Solution Steps
To evaluate the integral of the derivative of the product of two functions, we can use the fundamental theorem of calculus. The integral of the derivative of a function is simply the function itself plus a constant of integration.
Step 1: Define the Functions
Let \( f(x) \) and \( g(x) \) be two differentiable functions. We are interested in evaluating the integral of the derivative of their product, \( \int [f(x) \cdot g(x)]' \, dx \).
Step 2: Apply the Product Rule
Using the product rule of differentiation, we have:
\[
[f(x) \cdot g(x)]' = f(x) \cdot g'(x) + g(x) \cdot f'(x)
\]
Step 3: Integrate the Derivative
Now, we can integrate the expression obtained from the product rule:
\[
\int [f(x) \cdot g(x)]' \, dx = f(x) \cdot g(x) + C
\]
where \( C \) is the constant of integration.
Final Answer
Thus, the result of the integral is:
\[
\boxed{f(x) \cdot g(x) + C}
\]