The reaction involves the use of potassium permanganate (KMnO4\mathrm{KMnO}_4KMnO4) in an acidic medium (H3O+\mathrm{H}_3\mathrm{O}^+H3O+). This is a common oxidative condition used in organic chemistry to oxidize alkenes and alkynes to carboxylic acids or ketones, depending on the structure of the starting material.
To determine the major product, we need to know the structure of the starting material. Since the question does not specify the substrate, we will assume a general case where an alkene is being oxidized.
When an alkene is treated with KMnO4\mathrm{KMnO}_4KMnO4 in acidic conditions, it typically undergoes oxidative cleavage. Each carbon of the double bond is oxidized to a carboxylic acid if it is a terminal alkene, or to a ketone if it is an internal alkene.
Assuming a simple alkene such as ethene (C2H4\mathrm{C}_2\mathrm{H}_4C2H4), the major product of the reaction with KMnO4\mathrm{KMnO}_4KMnO4 and H3O+\mathrm{H}_3\mathrm{O}^+H3O+ would be acetic acid (CH3COOH\mathrm{CH}_3\mathrm{COOH}CH3COOH).
CH3COOH \boxed{\mathrm{CH}_3\mathrm{COOH}} CH3COOH
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