Questions: A city is growing at the rate of 0.9% annually. If there were 3,306,000 residents in the city in 1995, find how many (to the nearest ten-thousand) were living in that city in 2000. Use y=3,306,000(2.7)^0.009 t A. 400,000 B. 8,930,000 C. 3,490,000 D. 3,460,000

Solution Steps

To find the population of the city in 2000, we use the formula for exponential growth:

\[ y = 3,306,000 \times (2.7)^{0.009 \times t} \]

where \( t = 5 \) (the number of years from 1995 to 2000). Substituting the values, we have:

\[ y = 3,306,000 \times (2.7)^{0.009 \times 5} \]

Calculating this gives:

\[ y \approx 3,457,118.1216 \]

Next, we round the calculated population to the nearest ten-thousand:

\[ \text{Rounded Population} \approx 3,460,000 \]

Final Answer