Questions: =√(5199.797115)^2(1+255.060/6378137)(1+353.221/6378137)+(353.221-255.060)^2

=√(5199.797115)^2(1+255.060/6378137)(1+353.221/6378137)+(353.221-255.060)^2
Transcript text: $=\sqrt{(5199.797115)^{2}\left(1+\frac{255.060}{6378137}\right)\left(1+\frac{353.221}{6378137}\right)+(353.221-255.060)^{2}}$
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Solution

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Solution Steps

To solve the given expression, we need to break it down into smaller parts and compute each part step by step. We will:

  1. Compute the squared value of 5199.797115.
  2. Compute the fractions \(\frac{255.060}{6378137}\) and \(\frac{353.221}{6378137}\).
  3. Add 1 to each of the fractions computed in step 2.
  4. Multiply the results from steps 1 and 3.
  5. Compute the difference \(353.221 - 255.060\) and then square it.
  6. Add the results from steps 4 and 5.
  7. Finally, take the square root of the result from step 6.
Step 1: Compute \( a^2 \)

We start by calculating \( a^2 \) where \( a = 5199.797115 \): \[ a^2 = (5199.797115)^2 = 27037890.037162326 \]

Step 2: Compute \( 1 + \frac{b}{d} \)

Next, we compute \( 1 + \frac{b}{d} \) where \( b = 255.060 \) and \( d = 6378137 \): \[ 1 + \frac{b}{d} = 1 + \frac{255.060}{6378137} = 1.0000399897336794 \]

Step 3: Compute \( 1 + \frac{c}{d} \)

Now, we compute \( 1 + \frac{c}{d} \) where \( c = 353.221 \): \[ 1 + \frac{c}{d} = 1 + \frac{353.221}{6378137} = 1.0000553799644003 \]

Step 4: Compute the product

We multiply the results from Step 1 and Step 2 and Step 3: \[ \text{part4} = a^2 \cdot \left(1 + \frac{b}{d}\right) \cdot \left(1 + \frac{c}{d}\right) = 27037890.037162326 \cdot 1.0000399897336794 \cdot 1.0000553799644003 = 27040468.692450806 \]

Step 5: Compute \( (c - b)^2 \)

Next, we calculate \( (c - b)^2 \): \[ (c - b)^2 = (353.221 - 255.060)^2 = (98.161)^2 = 9635.581921 \]

Step 6: Compute the final result

Finally, we add the results from Step 4 and Step 5, and take the square root: \[ \text{result} = \sqrt{\text{part4} + \text{part5}} = \sqrt{27040468.692450806 + 9635.581921} = \sqrt{27050404.274371827} \approx 5200.971474097104 \]

Final Answer

The final result is: \[ \boxed{5200.9715} \]

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