Questions: pts) 6) Write the equation of the given line in slope intercept form.

pts) 6) Write the equation of the given line in slope intercept form.
Transcript text: pts) 6) Write the equation of the given line in slope intercept form.
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Solution

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Solution Steps

Step 1: Find two points on the line

The line passes through the points $(0, -3)$ and $(-3, 0)$.

Step 2: Calculate the slope

The slope of the line is given by $m = \frac{y_2 - y_1}{x_2 - x_1}$. Using the points $(0, -3)$ and $(-3, 0)$, we have $m = \frac{0 - (-3)}{-3 - 0} = \frac{3}{-3} = -1$.

Step 3: Determine the y-intercept

The y-intercept is the point where the line crosses the y-axis. From the graph, this occurs at $(0, -3)$, so the y-intercept is $b = -3$.

Step 4: Write the equation in slope-intercept form

The slope-intercept form of a linear equation is $y = mx + b$. We found $m = -1$ and $b = -3$. Therefore, the equation of the line is $y = -x - 3$.

Final Answer

$y = -x - 3$

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