Questions: Question The density of an unknown crystal is 2.65 g/mL. If a 4.46 g sample of the crystal is added to a graduated cylinder containing 25.0 mL of water, what will the volume read? - Round your answer to one decimal place. Provide your answer below: mL

Solution Steps

To find the volume of the crystal, we use the formula for density: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \] Rearranging the formula to solve for volume: \[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \] Given: \[ \text{Mass} = 4.46 \, \text{g} \] \[ \text{Density} = 2.65 \, \frac{\text{g}}{\text{mL}} \] Substituting the values: \[ \text{Volume} = \frac{4.46 \, \text{g}}{2.65 \, \frac{\text{g}}{\text{mL}}} = 1.6830 \, \text{mL} \]

The initial volume of water in the graduated cylinder is 25.0 mL. When the crystal is added, the total volume will be the sum of the initial water volume and the volume of the crystal: \[ \text{Total Volume} = \text{Initial Volume} + \text{Volume of Crystal} \] Substituting the values: \[ \text{Total Volume} = 25.0 \, \text{mL} + 1.6830 \, \text{mL} = 26.6830 \, \text{mL} \]

Rounding 26.6830 mL to one decimal place: \[ 26.6830 \approx 26.7 \, \text{mL} \]

Final Answer