Questions: The table shows the distribution of family size in a certain U.S. city. t family is selected at random from the city. Find the probability that the size of the family is between 2 and 5 inclusive. Round approximations to three decimal places.
Family Size Probability
2 0.442
3 0.236
4 0.195
5 0.071
6 0.037
7+ 0.019
A. 0.873
B. 0.431
C. 0.513
D. 0.944
Transcript text: The table shows the distribution of family size in a certain U.S. city. $t$ family is selected at random from the city. Find the probability that the size of the family is between 2 and 5 inclusive. Round approximations to three decimal places.
\begin{tabular}{|c|c|}
\hline Family Size & Probability \\
\hline 2 & 0.442 \\
\hline 3 & 0.236 \\
\hline 4 & 0.195 \\
\hline 5 & 0.071 \\
\hline 6 & 0.037 \\
\hline $7+$ & 0.019 \\
\hline
\end{tabular}
A. 0.873
B. 0.431
C. 0.513
D. 0.944
Solution
Solution Steps
Step 1: Identify the relevant probabilities
The question asks for the probability that the family size is between 2 and 5 inclusive. From the table, the relevant probabilities are:
Family size 2: \( P(2) = 0.442 \)
Family size 3: \( P(3) = 0.236 \)
Family size 4: \( P(4) = 0.195 \)
Family size 5: \( P(5) = 0.071 \)
Step 2: Sum the probabilities
To find the probability that the family size is between 2 and 5 inclusive, we sum the probabilities for family sizes 2, 3, 4, and 5:
\[
P(2 \leq \text{Family Size} \leq 5) = P(2) + P(3) + P(4) + P(5)
\]
\[
P(2 \leq \text{Family Size} \leq 5) = 0.442 + 0.236 + 0.195 + 0.071
\]
\[
P(2 \leq \text{Family Size} \leq 5) = 0.944
\]
Step 3: Round the result
The result \( 0.944 \) is already rounded to three decimal places.
Final Answer
The probability that the family size is between 2 and 5 inclusive is \(\boxed{0.944}\). The correct choice is D.