Questions: For what input values of g(x)=(x^2+7x+10)/(x^2-5x+6) are the output values of g(x)=0?
Transcript text: For what input values of $g(x)=\frac{x^{2}+7 x+10}{x^{2}-5 x+6}$ are the output values of $g(x)=0$ ?
Solution
Solution Steps
To find the input values for which \( g(x) = 0 \), we need to determine when the numerator of the function is zero, since a fraction is zero when its numerator is zero (and the denominator is not zero). Therefore, we solve the equation \( x^2 + 7x + 10 = 0 \). We also need to ensure that these solutions do not make the denominator zero by checking \( x^2 - 5x + 6 \neq 0 \).
Step 1: Solve the Numerator
To find the input values for which \( g(x) = 0 \), we set the numerator equal to zero:
\[
x^2 + 7x + 10 = 0
\]
Factoring the quadratic, we get:
\[
(x + 5)(x + 2) = 0
\]
Thus, the solutions are:
\[
x = -5 \quad \text{and} \quad x = -2
\]
Step 2: Solve the Denominator
Next, we need to ensure that these solutions do not make the denominator zero. We set the denominator equal to zero:
\[
x^2 - 5x + 6 = 0
\]
Factoring this quadratic, we find:
\[
(x - 2)(x - 3) = 0
\]
The solutions are:
\[
x = 2 \quad \text{and} \quad x = 3
\]
Step 3: Validate Solutions
We check if the solutions from the numerator, \( x = -5 \) and \( x = -2 \), are also solutions to the denominator. Since neither \( -5 \) nor \( -2 \) is equal to \( 2 \) or \( 3 \), both values are valid.
Final Answer
The input values for which \( g(x) = 0 \) are:
\[
\boxed{-5 \text{ and } -2}
\]