For two lines to be parallel, their slopes must be equal. The general form of a line is ax+by+c=0ax + by + c = 0ax+by+c=0, and the slope of the line is given by −ab-\frac{a}{b}−ba.
For the line d1:2x+(m+1)y−4=0d_1: 2x + (m+1)y - 4 = 0d1:2x+(m+1)y−4=0, the slope is: −2m+1 -\frac{2}{m+1} −m+12
For the line d2:−x+2my+1=0d_2: -x + 2my + 1 = 0d2:−x+2my+1=0, the slope is: −−12m=12m -\frac{-1}{2m} = \frac{1}{2m} −2m−1=2m1
Since the lines are parallel, set the slopes equal to each other: −2m+1=12m -\frac{2}{m+1} = \frac{1}{2m} −m+12=2m1
Cross-multiply to solve for mmm: −2⋅2m=1⋅(m+1) -2 \cdot 2m = 1 \cdot (m+1) −2⋅2m=1⋅(m+1) −4m=m+1 -4m = m + 1 −4m=m+1
Add 4m4m4m to both sides: 0=5m+1 0 = 5m + 1 0=5m+1
Subtract 1 from both sides: −1=5m -1 = 5m −1=5m
Divide by 5: m=−15 m = -\frac{1}{5} m=−51
The value of mmm that makes the lines parallel is: m=−15 \boxed{m = -\frac{1}{5}} m=−51
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