Questions: Question 5 1 / 1 pts 5. What is the product of elimination reaction shown in the box? A) C) B) D)

Solution Steps

The question states that this is an elimination reaction. Specifically, with a strong, bulky base like _t_-BuOK, it favors an E2 reaction mechanism.

E2 reactions favor the formation of the more substituted alkene. In this case, the bromine (leaving group) is on a secondary carbon. The _t_-BuOK will abstract a proton from a neighboring carbon, resulting in the formation of a double bond. Because the carbon adjacent to the bromine bearing carbon is also secondary, the major product will be the most substituted internal alkene.

Option D shows the formation of the correct alkene product. The other options show either substitution products or less substituted alkenes which are not favored under these conditions.

Final Answer: The correct answer is D.