Questions: The sample space listing the eight simple events that are possible when a couple has three children is bbb, bbg, bgb, bgg, gbb, gbg, ggb, ggg. After identifying the sample space for a couple having four children, find the probability of getting four girls and no boys.
Identify the sample space for a couple having four children.
Transcript text: The sample space listing the eight simple events that are possible when a couple has three children is $\{b b b, b b g, b g b, b g g, g b b, gbg, ggb, ggg\}$. After identifying the sample space for a couple having four children, find the probability of getting four girls and no boys.
Identify the sample space for a couple having four children. $\square$
Solution
Solution Steps
Step 1: Identify the Sample Space for \(n\) Children
The total number of possible outcomes for \(n=4\) children is \(2^4 = 16\).
Step 2: Calculate the Number of Favorable Outcomes
The number of ways to have \(k=4\) children of a specific gender out of \(n=4\) is given by \(\binom{n}{k} = \frac{n!}{k!(n-k)!} = 1\).
Step 3: Calculate the Probability
The probability of having \(k=4\) children of a specific gender out of \(n=4\) is \(\frac{\binom{n}{k}}{2^n} = 0.06\).
Final Answer:
The probability of having \(k=4\) children of a specific gender when a couple has \(n=4\) children is approximately 0.06.