Questions: The half-life of sodium-22 is 2.6 years. If there are initially 40 grams of sodium-22, find a formula that gives the amount S, in grams, remaining after t years.

The half-life of sodium-22 is 2.6 years. If there are initially 40 grams of sodium-22, find a formula that gives the amount S, in grams, remaining after t years.
Transcript text: The half-life of sodium-22 is 2.6 years. If there are initially 40 grams of sodium-22, find a formula that gives the amount $S$, in grams, remaining after $t$ years.
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Solution

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Solution Steps

Step 1: Understanding the Half-Life Formula

The half-life formula for radioactive decay is given by: S(t)=S0(12)tT S(t) = S_0 \left(\frac{1}{2}\right)^{\frac{t}{T}} where:

  • S(t) S(t) is the amount of substance remaining after time t t ,
  • S0 S_0 is the initial amount of the substance,
  • T T is the half-life of the substance,
  • t t is the time elapsed.
Step 2: Identifying Given Values

From the problem, we have:

  • The half-life T T of sodium-22 is 2.6 years.
  • The initial amount S0 S_0 is 40 grams.
Step 3: Substituting Values into the Formula

Substitute S0=40 S_0 = 40 grams and T=2.6 T = 2.6 years into the half-life formula: S(t)=40(12)t2.6 S(t) = 40 \left(\frac{1}{2}\right)^{\frac{t}{2.6}}

Final Answer

The formula that gives the amount S S , in grams, remaining after t t years is: S(t)=40(12)t2.6 \boxed{S(t) = 40 \left(\frac{1}{2}\right)^{\frac{t}{2.6}}}

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