Questions: Suppose the line y=2.8333 x-22.4967 describes the relation between the club-head speed (in miles per hour), x and the distance a golf ball travels (in yards), y. (a) Predict the distance a golf ball will travel if the club-head speed is 100 mph. (b) Suppose the observed distance a golf ball traveled when the club-head speed was 100 mph was 265 yards. What is the residual? (a) The golf ball will travel yards. (Round to the nearest tenth as needed.)

Suppose the line y=2.8333 x-22.4967 describes the relation between the club-head speed (in miles per hour), x and the distance a golf ball travels (in yards), y.
(a) Predict the distance a golf ball will travel if the club-head speed is 100 mph.
(b) Suppose the observed distance a golf ball traveled when the club-head speed was 100 mph was 265 yards. What is the residual?
(a) The golf ball will travel yards.
(Round to the nearest tenth as needed.)
Transcript text: Part 1 of 2 0 of 1 Point Suppose the line $y=2.8333 x-22.4967$ describes the relation between the club-head speed (in miles per hour), $x$ and the distance a golf ball travels (in yards), $y$. (a) Predict the distance a golf ball will travel if the club-head speed is 100 mph . (b) Suppose the observed distance a golf ball traveled when the club-head speed was 100 mph was 265 yards. What is the residual? (a) The golf ball will travel $\square$ yards. (Round to the nearest tenth as needed.)
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Solution

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Solution Steps

To solve this problem, we will use the given linear equation to predict the distance a golf ball will travel for a given club-head speed. For part (a), substitute the given club-head speed into the equation to find the predicted distance. For part (b), calculate the residual by subtracting the predicted distance from the observed distance.

Step 1: Predict the Distance

To predict the distance y y a golf ball will travel for a club-head speed x=100 x = 100 mph, we use the linear equation:

y=2.8333x22.4967 y = 2.8333x - 22.4967

Substituting x=100 x = 100 :

y=2.8333(100)22.4967=260.8333 y = 2.8333(100) - 22.4967 = 260.8333

Rounding to the nearest tenth, we find:

y260.8 y \approx 260.8

Step 2: Calculate the Residual

The residual is calculated as the difference between the observed distance and the predicted distance. Given the observed distance is 265 265 yards, we compute:

Residual=Observed DistancePredicted Distance=265260.8333=4.199999999999989 \text{Residual} = \text{Observed Distance} - \text{Predicted Distance} = 265 - 260.8333 = 4.199999999999989

Rounding to four significant digits, we have:

Residual4.2 \text{Residual} \approx 4.2

Final Answer

The predicted distance is 260.8 \boxed{260.8} yards, and the residual is 4.2 \boxed{4.2} yards.

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