Questions: Suppose the line y=2.8333 x-22.4967 describes the relation between the club-head speed (in miles per hour), x and the distance a golf ball travels (in yards), y.
(a) Predict the distance a golf ball will travel if the club-head speed is 100 mph.
(b) Suppose the observed distance a golf ball traveled when the club-head speed was 100 mph was 265 yards. What is the residual?
(a) The golf ball will travel yards.
(Round to the nearest tenth as needed.)
Transcript text: Part 1 of 2
0 of 1 Point
Suppose the line $y=2.8333 x-22.4967$ describes the relation between the club-head speed (in miles per hour), $x$ and the distance a golf ball travels (in yards), $y$.
(a) Predict the distance a golf ball will travel if the club-head speed is 100 mph .
(b) Suppose the observed distance a golf ball traveled when the club-head speed was 100 mph was 265 yards. What is the residual?
(a) The golf ball will travel $\square$ yards.
(Round to the nearest tenth as needed.)
Solution
Solution Steps
To solve this problem, we will use the given linear equation to predict the distance a golf ball will travel for a given club-head speed. For part (a), substitute the given club-head speed into the equation to find the predicted distance. For part (b), calculate the residual by subtracting the predicted distance from the observed distance.
Step 1: Predict the Distance
To predict the distance \( y \) a golf ball will travel for a club-head speed \( x = 100 \) mph, we use the linear equation:
\[
y = 2.8333x - 22.4967
\]
Substituting \( x = 100 \):
\[
y = 2.8333(100) - 22.4967 = 260.8333
\]
Rounding to the nearest tenth, we find:
\[
y \approx 260.8
\]
Step 2: Calculate the Residual
The residual is calculated as the difference between the observed distance and the predicted distance. Given the observed distance is \( 265 \) yards, we compute: