Questions: A mechanic changing the spark plugs in a car notes that the instruction manual calls for a torque with a magnitude of 43 N . m . If the mechanic grasps the wrench as shown in the figure below, determine the magnitude (in N ) of the force she must exert on the wrench.

A mechanic changing the spark plugs in a car notes that the instruction manual calls for a torque with a magnitude of 43 N . m . If the mechanic grasps the wrench as shown in the figure below, determine the magnitude (in N ) of the force she must exert on the wrench.
Transcript text: A mechanic changing the spark plugs in a car notes that the instruction manual calls for a torque with a magnitude of 43 N . m . If the mechanic grasps the wrench as shown in the figure below, determine the magnitude (in N ) of the force she must exert on the wrench. $\square$ N Additional Materials
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Solution

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Solution Steps

Step 1: Identify the Given Values
  • Torque (\( \tau \)) = 43 N·m
  • Length of the wrench (\( r \)) = 0.30 m
  • Angle (\( \theta \)) = 60°
Step 2: Understand the Relationship Between Torque, Force, and Angle

The torque (\( \tau \)) is given by the formula: \[ \tau = r \cdot F \cdot \sin(\theta) \] where:

  • \( \tau \) is the torque,
  • \( r \) is the length of the wrench,
  • \( F \) is the force applied,
  • \( \theta \) is the angle between the force and the wrench.
Step 3: Rearrange the Formula to Solve for Force

Rearrange the formula to solve for \( F \): \[ F = \frac{\tau}{r \cdot \sin(\theta)} \]

Step 4: Substitute the Given Values into the Formula

Substitute the given values into the formula: \[ F = \frac{43 \, \text{N·m}}{0.30 \, \text{m} \cdot \sin(60°)} \]

Step 5: Calculate the Sine of the Angle

Calculate \( \sin(60°) \): \[ \sin(60°) = \frac{\sqrt{3}}{2} \approx 0.866 \]

Step 6: Perform the Final Calculation

Substitute \( \sin(60°) \) into the formula and calculate \( F \): \[ F = \frac{43}{0.30 \cdot 0.866} \] \[ F \approx \frac{43}{0.2598} \] \[ F \approx 165.5 \, \text{N} \]

Final Answer

The magnitude of the force the mechanic must exert on the wrench is approximately \( 165.5 \, \text{N} \).

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