Questions: The number of computers sold per day at a computer store is defined by the probability distribution below. Complete parts (a) through (d). X: 0, 1, 2, 3, 4, 5, 6 P(x): 0.04, 0.07, 0.16, 0.22, 0.21, 0.28, 0.02 a. Find P(3 ≤ x<6). P(3 ≤ x<6)=0.71 (Do not round.) b. Find P(x>3). P(x>3)=

The number of computers sold per day at a computer store is defined by the probability distribution below. Complete parts (a) through (d). X: 0, 1, 2, 3, 4, 5, 6 P(x): 0.04, 0.07, 0.16, 0.22, 0.21, 0.28, 0.02 a. Find P(3 ≤ x<6). P(3 ≤ x<6)=0.71 (Do not round.) b. Find P(x>3). P(x>3)=
Transcript text: The number of computers sold per day at a computer store is defined by the probability distribution below. Complete parts (a) through (d). \begin{tabular}{lccccccc} \hline X & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline $\mathrm{P}(\mathrm{x})$ & 0.04 & 0.07 & 0.16 & 0.22 & 0.21 & 0.28 & 0.02 \\ \hline \end{tabular} a. Find $P(3 \leq x<6)$. \[ P(3 \leq x<6)=0.71 \text { (Do not round.) } \] b. Find $P(x>3)$. \[ P(x>3)= \] $\square$ (Do not round.)
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Solution

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Solution Steps

Step 1: Calculate \( P(3 \leq x < 6) \)

To find \( P(3 \leq x < 6) \), we sum the probabilities for \( x = 3, 4, \) and \( 5 \):

\[ P(3 \leq x < 6) = P(3) + P(4) + P(5) = 0.22 + 0.21 + 0.28 = 0.71 \]

Step 2: Calculate \( P(x > 3) \)

To find \( P(x > 3) \), we sum the probabilities for \( x = 4, 5, \) and \( 6 \):

\[ P(x > 3) = P(4) + P(5) + P(6) = 0.21 + 0.28 + 0.02 = 0.51 \]

Final Answer

The results are:

  • \( P(3 \leq x < 6) = 0.71 \)
  • \( P(x > 3) = 0.51 \)

Thus, the final answers are: \[ \boxed{P(3 \leq x < 6) = 0.71} \] \[ \boxed{P(x > 3) = 0.51} \]

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