Questions: A random variable is binomially distributed with n=16 and π=.40. The expected value and standard deviation of the variables are Multiple Choice 2.00 and 1.24. 4.80 and 4.00 . 6.40 and 1.96. 2.00 and 1.20.

A random variable is binomially distributed with n=16 and π=.40. The expected value and standard deviation of the variables are

Multiple Choice
2.00 and 1.24.
4.80 and 4.00 .
6.40 and 1.96.
2.00 and 1.20.
Transcript text: A random variable is binomially distributed with $n=16$ and $\pi=.40$. The expected value and standard deviation of the variables are Multiple Choice 2.00 and 1.24. 4.80 and 4.00 . 6.40 and 1.96. 2.00 and 1.20 .
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Solution

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Solution Steps

Step 1: Calculate the Mean

The expected value (mean) of a binomially distributed random variable can be calculated using the formula:

\[ \mu = n \cdot p \]

Substituting the given values \( n = 16 \) and \( p = 0.40 \):

\[ \mu = 16 \cdot 0.40 = 6.4 \]

Step 2: Calculate the Variance

The variance of a binomially distributed random variable is given by the formula:

\[ \sigma^2 = n \cdot p \cdot q \]

where \( q = 1 - p \). Thus, \( q = 1 - 0.40 = 0.60 \). Now substituting the values:

\[ \sigma^2 = 16 \cdot 0.40 \cdot 0.60 = 3.84 \]

Step 3: Calculate the Standard Deviation

The standard deviation is the square root of the variance:

\[ \sigma = \sqrt{n \cdot p \cdot q} = \sqrt{3.84} \approx 1.96 \]

Final Answer

The expected value and standard deviation of the random variable are:

\[ \boxed{\mu = 6.4 \text{ and } \sigma = 1.96} \]

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