We are given the number \(38_{\text{nine}}\), which is in base nine. Our goal is to convert this number to the base-ten system.
In base nine, the number \(38_{\text{nine}}\) can be expanded as: \[ 3 \times 9^1 + 8 \times 9^0 \]
Calculate the value of each term: \[ 3 \times 9^1 = 3 \times 9 = 27 \] \[ 8 \times 9^0 = 8 \times 1 = 8 \]
Add the results of the two terms: \[ 27 + 8 = 35 \]
\[ \boxed{35} \]
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