Questions: In 2022, Antarctica recorded record-breaking high temperatures. Consider the monthly average temperature (in degrees Celsius) for 2021 displayed in the table. -15.7, -21.9, -30.4, -35.4, -30.6, -29.7, -30.5, -39.8, -35.5, -28.9, -20.6, -16.5 Use the stats tool to find the mean and standard deviation of the temperature data. Round answers to 2 decimal places. The mean is and the standard deviation is

In 2022, Antarctica recorded record-breaking high temperatures. Consider the monthly average temperature (in degrees Celsius) for 2021 displayed in the table. -15.7, -21.9, -30.4, -35.4, -30.6, -29.7, -30.5, -39.8, -35.5, -28.9, -20.6, -16.5

Use the stats tool to find the mean and standard deviation of the temperature data. Round answers to 2 decimal places.

The mean is and the standard deviation is
Transcript text: In 2022, Antarctica recorded record-breaking high temperatures. Consider the monthly average temperature (in degrees Celsius) for 2021 displayed in the table. $-15.7$ -21.9 $-30.4$ $-35.4$ $-30.6$ $-29.7$ $-30.5$ $-39.8$ $-35.5$. $-28.9$ - 20.6 $-16.5$ Use the stats tool to find the mean and standard deviation of the temperature data. Round answers to 2 decimal places. The mean is $\square$ and the standard deviation is $\square$
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Solution

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Solution Steps

Step 1: Calculate the Mean

To find the mean temperature, we use the formula:

\[ \mu = \frac{\sum_{i=1}^N x_i}{N} \]

where \( N \) is the number of observations and \( x_i \) are the temperature values. For our data:

\[ \sum_{i=1}^{12} x_i = -335.5 \quad \text{and} \quad N = 12 \]

Thus, the mean temperature is calculated as:

\[ \mu = \frac{-335.5}{12} = -27.96 \]

Step 2: Calculate the Variance

The variance is calculated using the formula:

\[ \sigma^2 = \frac{\sum (x_i - \mu)^2}{N} \]

Substituting the values, we find:

\[ \sigma^2 = 54.02 \]

Step 3: Calculate the Standard Deviation

The standard deviation is the square root of the variance:

\[ \sigma = \sqrt{\sigma^2} = \sqrt{54.02} \approx 7.35 \]

Final Answer

The mean temperature is \( \mu = -27.96 \) and the standard deviation is \( \sigma \approx 7.35 \).

Thus, the final answers are: \[ \boxed{\mu = -27.96} \] \[ \boxed{\sigma \approx 7.35} \]

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