Questions: A binomial experiment has the given number of trials n and the given success probability p. n=9, p=0.2 Part 1 of 3 (a) Determine the probability P(5). Round the answer to at least four decimal places. P(5)=0.0165 Part: 1 / 3 Part 2 of 3 (b) Find the mean. Round the answer to two decimal places. The mean is

A binomial experiment has the given number of trials n and the given success probability p.

n=9, p=0.2

Part 1 of 3
(a) Determine the probability P(5). Round the answer to at least four decimal places.

P(5)=0.0165

Part: 1 / 3

Part 2 of 3
(b) Find the mean. Round the answer to two decimal places.

The mean is
Transcript text: A binomial experiment has the given number of trials $n$ and the given success probability $p$. \[ n=9, p=0.2 \] Part 1 of 3 (a) Determine the probability $P(5)$. Round the answer to at least four decimal places. \[ P(5)=0.0165 \] Part: $1 / 3$ Part 2 of 3 (b) Find the mean. Round the answer to two decimal places. The mean is $\square$
failed

Solution

failed
failed

Solution Steps

To solve these problems, we need to use the properties of a binomial distribution.

(a) For the probability \( P(5) \), we use the binomial probability formula: \[ P(k) = \binom{n}{k} p^k (1-p)^{n-k} \] where \( n \) is the number of trials, \( k \) is the number of successes, and \( p \) is the probability of success.

(b) The mean of a binomial distribution is given by: \[ \text{Mean} = n \times p \]

Step 1: Calculate \( P(5) \)

To find the probability of getting exactly 5 successes in 9 trials with a success probability of 0.2, we use the binomial probability formula:

\[ P(5) = \binom{9}{5} (0.2)^5 (0.8)^{4} \]

Calculating this gives:

\[ P(5) \approx 0.0165 \]

Step 2: Calculate the Mean

The mean of a binomial distribution is calculated using the formula:

\[ \text{Mean} = n \times p \]

Substituting the values:

\[ \text{Mean} = 9 \times 0.2 = 1.8 \]

Final Answer

The results are:

  • \( P(5) \approx 0.0165 \)
  • Mean \( = 1.8 \)

Thus, the final boxed answers are:

\[ \boxed{P(5) \approx 0.0165} \]

\[ \boxed{\text{Mean} = 1.8} \]

Was this solution helpful?
failed
Unhelpful
failed
Helpful