Questions: Un container per il trasporto delle merci, che ha un volume di 3,83 x 10^7 cm^3 e una massa di 2,45 x 10^6 g, viene riempito con 1,525 x 10^7 g di merce. Calcola la densità media del container pieno in g / cm^3. [4,62 x 10^-1 g / cm^3]

Solution Steps

• Volume of the container ($V$): $3.83 \times 10^7 \, \text{cm}^3$
• Mass of the empty container ($m_{\text{container}}$): $2.45 \times 10^6 \, \text{g}$
• Mass of the goods ($m_{\text{goods}}$): $1.525 \times 10^7 \, \text{g}$

The total mass ($m_{\text{total}}$) is the sum of the mass of the empty container and the mass of the goods: $$m_{\text{total}} = m_{\text{container}} + m_{\text{goods}}$$ $$m_{\text{total}} = 2.45 \times 10^6 \, \text{g} + 1.525 \times 10^7 \, \text{g}$$ $$m_{\text{total}} = 1.77 \times 10^7 \, \text{g}$$

Density ($\rho$) is defined as mass per unit volume: $$\rho = \frac{m_{\text{total}}}{V}$$ $$\rho = \frac{1.77 \times 10^7 \, \text{g}}{3.83 \times 10^7 \, \text{cm}^3}$$ $$\rho \approx 0.462 \, \text{g/cm}^3$$

Final Answer