Questions: Measurement and Matter Distinguishing solid, liquid and gas phases of a pure substance There are three sets of sketches below, showing the same pure molecular compound (hydrogen chloride) at different temperatures. The sketches are drawn as if a sample of hydrogen chloride were under a microscope. Only one sketch in each set is correct. Use the slider to choose the correct sketch in each set. You may need the following information: melting point of HCl: -114.8°C boiling point of HCl: -85.1°C A B C -143 °C -95 °C -53 °C

Measurement and Matter
Distinguishing solid, liquid and gas phases of a pure substance
There are three sets of sketches below, showing the same pure molecular compound (hydrogen chloride) at different temperatures. The sketches are drawn as if a sample of hydrogen chloride were under a microscope. Only one sketch in each set is correct.
Use the slider to choose the correct sketch in each set. You may need the following information:
melting point of HCl: -114.8°C
boiling point of HCl: -85.1°C

A
B
C
-143 °C
-95 °C
-53 °C

Transcript text: Measurement and Matter Distinguishing solid, liquid and gas phases of a pure substance There are three sets of sketches below, showing the same pure molecular compound (hydrogen chloride) at different temperatures. The sketches are drawn as if a sample of hydrogen chloride were under a microscope. Only one sketch in each set is correct. Use the slider to choose the correct sketch in each set. You may need the following information: melting point of $\mathrm{HCl}:-114.8^{\circ} \mathrm{C}$ boiling point of HCl: $-85.1^{\circ} \mathrm{C}$ A B C $-143 .{ }^{\circ} \mathrm{C}$ $-95 .{ }^{\circ} \mathrm{C}$ $-53 .{ }^{\circ} \mathrm{C}$

Solution

Solution Steps

Step 1: Analyze the melting and boiling points of HCl

The melting point of HCl is -114.8 °C, and the boiling point is -85.1 °C. This means HCl is a solid below -114.8 °C, a liquid between -114.8 °C and -85.1 °C, and a gas above -85.1 °C.

Step 2: Determine the correct sketch for A (-143 °C)

Since -143 °C is below the melting point of HCl, it will be in the solid phase. The molecules in a solid are tightly packed and ordered. Thus, the correct sketch for A is 1, which shows a solid structure.

Step 3: Determine the correct sketch for B (-95 °C)

Since -95 °C is between the melting and boiling points, HCl will be in the liquid phase. The molecules in a liquid are close together but can move around. Thus, the correct sketch for B is 2, which shows the molecules close together but not in a fixed arrangement like a solid.

Final Answer:

A: 1 B: 2 C: 4

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